![\"\"](\"/images/stars/stars-10.gif\")
You can put this solution on YOUR website!
the slope and y-intercept point of y=x/2-8?\r
\n" ); document.write( "\n" ); document.write( "y=x/2-8
\n" ); document.write( "That is y = (1/2)x+(-8) ----(1)
\n" ); document.write( "(1) is in the form y =(m)x +b ----(*) which is called the slope and y-intercept form of an equation. Here m is the slope of the line and b is the y-intercept
\n" ); document.write( "Therefore in (1),the slope = (1/2) and the y-intercept = (-8)
\n" ); document.write( "Slope positive implies the line's journey is from the I quadrant to the III quadrant (as the line makes an acute angle with the x-axis) and since the
\n" ); document.write( "y-intercept is negative,the line travels via the IV quadrant.
\n" ); document.write( "It cuts off a length = 8 units on the y-axis below the origin.
\n" ); document.write( "Supposing the line meets the y-axis at P then P is on the y-axis with P below the x-axis and OP = 8 unints
\n" ); document.write( "Therefore the point P has co-ordinates (0,-8)
\n" ); document.write( "Note: How do we recognise the slope to be (1/2) and the y-intercept to be (-8)
\n" ); document.write( "The rule is when the coefficient of y is 1 (the value one) on one side of the equation,(say the LHS)then the coefficient of x on the other side of the equation(RHS) is the slope of the line and the free constant on the other side (RHS)is the y-intercept of the line. \n" ); document.write( "