document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221551>Question 221551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi agian, I have asked this question on a number of occasions but have so far only received a small amount of help. Can someone please show me how to simplify the following? I need to give answers in the form a+bi ( a, b are real numbers)<BR>\n" );
document.write( "a) i^15<BR>\n" );
document.write( "b) (2-i) / (5+i)<BR>\n" );
document.write( "Thanks, -Nick. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166151 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) i^15<BR>\n" );
document.write( "i^15 = i^3 = -1*i<BR>\n" );
document.write( "= -i<BR>\n" );
document.write( "------<BR>\n" );
document.write( "b) (2-i) / (5+i)<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Multiply NUM and DEN by the conjugate of the DEN<BR>\n" );
document.write( "= (2-i)*(5-i)/(5+i)*(5-i)<BR>\n" );
document.write( "= (10 - 1 - 7i)/(25+1)<BR>\n" );
document.write( "= (9-7i)/26<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );