document.write( "Question 221511: give exact and approximate solutions to three decimal places\r
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\n" ); document.write( "\n" ); document.write( "x^2+5x-3=0
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Algebra.Com's Answer #166131 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B5x-3=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"x%5E2%2B5x-3\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=5\", and \"C=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%285%29+%2B-+sqrt%28+%285%29%5E2-4%281%29%28-3%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=5\", and \"C=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25-4%281%29%28-3%29+%29%29%2F%282%281%29%29\" Square \"5\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25--12+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-3%29\" to get \"-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25%2B12+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%2825--12%29\" as \"sqrt%2825%2B12%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+37+%29%29%2F%282%281%29%29\" Add \"25\" to \"12\" to get \"37\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+37+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5%2Bsqrt%2837%29%29%2F%282%29\" or \"x+=+%28-5-sqrt%2837%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+%28-5%2Bsqrt%2837%29%29%2F%282%29\" or \"x+=+%28-5-sqrt%2837%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=0.541\" or \"x=-5.541\"
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