document.write( "Question 221507: I have to factor each trinomial\r
\n" ); document.write( "\n" ); document.write( "3x^3 y^2 - 3x^2y^2 + 3xy^2\r
\n" ); document.write( "\n" ); document.write( "Can someone please help me understand this equation.\r
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Algebra.Com's Answer #166129 by drj(1380)\"\" \"About 
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I have to factor each trinomial\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E3y%5E2-3x%5E2y%5E2%2B3xy%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Can someone please help me understand this equation.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Find a factor common to all three terms. Start with a number 3 since it's common to all three terms and we factor 3 out.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E3y%5E2-3x%5E2y%5E2%2B3xy%5E2=3%28x%5E3y%5E2-3x%5E2y%5E2%2Bxy%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "Step 2. Now look at the x-terms with the highest exponent in x that is common to all three terms. In this case, it's simply x and we factor x out.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E3y%5E2-3x%5E2y%5E2%2Bxy%5E2%29=3x%28x%5E2y%5E2-3xy%5E2%2By%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Now look at the y-terms and we observe that \"y%5E2\" is common to all three terms and we factor \"y%5E2\" out.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%28x%5E2y%5E2-3xy%5E2%2By%5E2%29=3xy%5E2%28x%5E2-3x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. ANSWER: \"3x%5E3y%5E2-3x%5E2y%5E2%2B3xy%5E2=3xy%5E2%28x%5E2-3x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
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