document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221407>Question 221407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line with is perpendicular to the line y=&#8722;8x+9, and which passes through the point (&#8722;16, 6).\r<BR>\n" );
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document.write( "y=(1/8)x+b<BR>\n" );
document.write( "(6)=(1/8)(-16) + b<BR>\n" );
document.write( "-3=b\r<BR>\n" );
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document.write( "y=(1/8)x-3      <--- but this is wrong...  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166066 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can see that the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-8x%2B9 ALIGN=MIDDLE  ALT=\"y=-8x%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" > has a slope <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=-8 ALIGN=MIDDLE  ALT=\"m=-8\"   DISABLED_style= \"max-width:90%; height:auto;\" > and a y-intercept <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=9 ALIGN=MIDDLE  ALT=\"b=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Now to find the slope of the perpendicular line, simply flip the slope <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=-8 ALIGN=MIDDLE  ALT=\"m=-8\"   DISABLED_style= \"max-width:90%; height:auto;\" > to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=-1%2F8 ALIGN=MIDDLE  ALT=\"m=-1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Now change the sign to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=1%2F8 ALIGN=MIDDLE  ALT=\"m=1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So the perpendicular slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=1%2F8 ALIGN=MIDDLE  ALT=\"m=1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=1%2F8 ALIGN=MIDDLE  ALT=\"m=1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the coordinates of the given point <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left\(-16,6\right\)\">.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-y%5B1%5D=m%28x-x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the point slope formula\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-6=%281%2F8%29%28x--16%29 ALIGN=MIDDLE  ALT=\"y-6=%281%2F8%29%28x--16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=1%2F8 ALIGN=MIDDLE  ALT=\"m=1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5B1%5D=-16 ALIGN=MIDDLE  ALT=\"x%5B1%5D=-16\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5B1%5D=6 ALIGN=MIDDLE  ALT=\"y%5B1%5D=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-6=%281%2F8%29%28x%2B16%29 ALIGN=MIDDLE  ALT=\"y-6=%281%2F8%29%28x%2B16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Rewrite <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x--16 ALIGN=MIDDLE  ALT=\"x--16\"   DISABLED_style= \"max-width:90%; height:auto;\" > as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B16 ALIGN=MIDDLE  ALT=\"x%2B16\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-6=%281%2F8%29x%2B%281%2F8%29%2816%29 ALIGN=MIDDLE  ALT=\"y-6=%281%2F8%29x%2B%281%2F8%29%2816%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Distribute\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-6=%281%2F8%29x%2B2 ALIGN=MIDDLE  ALT=\"y-6=%281%2F8%29x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%281%2F8%29x%2B2%2B6 ALIGN=MIDDLE  ALT=\"y=%281%2F8%29x%2B2%2B6\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add 6 to both sides. \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%281%2F8%29x%2B8 ALIGN=MIDDLE  ALT=\"y=%281%2F8%29x%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms. \r<BR>\n" );
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document.write( "So the equation of the line perpendicular to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-8x%2B9 ALIGN=MIDDLE  ALT=\"y=-8x%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" > that goes through the point <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left\(-16,6\right\)\"> is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%281%2F8%29x%2B8 ALIGN=MIDDLE  ALT=\"y=%281%2F8%29x%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Here's a graph to visually verify our answer:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28500%2C+500%2C+-20%2C+2%2C+-8%2C+12%2C%0D%0Agraph%28500%2C+500%2C+-20%2C+2%2C+-8%2C+12%2C-8x%2B9%2C%281%2F8%29x%2B8%29%0D%0Acircle%28-16%2C6%2C0.08%29%2C%0D%0Acircle%28-16%2C6%2C0.10%29%2C%0D%0Acircle%28-16%2C6%2C0.12%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Graph of the original equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-8x%2B9 ALIGN=MIDDLE  ALT=\"y=-8x%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" > (red) and the perpendicular line <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%281%2F8%29x%2B8 ALIGN=MIDDLE  ALT=\"y=%281%2F8%29x%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" > (green) through the point <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left\(-16,6\right\)\">. \r<BR>\n" );
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document.write( "If you need more help or practice with this topic, check out this <a  rel=nofollow HREF=http://www.algebra.com/algebra/homework/Linear-equations/equation-parallel-or-perpendicular.solver>solver</a>.<BR>\n" );
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