document.write( "Question 221402: The difference of two positive numbers is 5 and the sum of their squares is 157. Find the numbers.\r
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Algebra.Com's Answer #166060 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"The difference of two positive numbers is 5\" means that \"x-y=5\" (note: this means that \"x%3Ey\")\r
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\n" ); document.write( "\n" ); document.write( "Also, because \"the sum of their squares is 157\" we know that \"x%5E2%2By%5E2=157\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-y=5\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-y=5-x\" Subtract x from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=x-5\" Multiply both sides by -1 and rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2=157\" Move onto the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B%28x-5%29%5E2=157\" Plug in \"y=x-5\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx%5E2-10x%2B25=157\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx%5E2-10x%2B25-157=0\" Subtract 157 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-10x-132=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"2x%5E2-10x-132\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=2\", \"B=-10\", and \"C=-132\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-10%29+%2B-+sqrt%28+%28-10%29%5E2-4%282%29%28-132%29+%29%29%2F%282%282%29%29\" Plug in \"A=2\", \"B=-10\", and \"C=-132\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+sqrt%28+%28-10%29%5E2-4%282%29%28-132%29+%29%29%2F%282%282%29%29\" Negate \"-10\" to get \"10\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+sqrt%28+100-4%282%29%28-132%29+%29%29%2F%282%282%29%29\" Square \"-10\" to get \"100\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+sqrt%28+100--1056+%29%29%2F%282%282%29%29\" Multiply \"4%282%29%28-132%29\" to get \"-1056\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+sqrt%28+100%2B1056+%29%29%2F%282%282%29%29\" Rewrite \"sqrt%28100--1056%29\" as \"sqrt%28100%2B1056%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+sqrt%28+1156+%29%29%2F%282%282%29%29\" Add \"100\" to \"1056\" to get \"1156\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+sqrt%28+1156+%29%29%2F%284%29\" Multiply \"2\" and \"2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B-+34%29%2F%284%29\" Take the square root of \"1156\" to get \"34\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2810+%2B+34%29%2F%284%29\" or \"x+=+%2810+-+34%29%2F%284%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2844%29%2F%284%29\" or \"x+=++%28-24%29%2F%284%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+11\" or \"x+=+-6\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible solutions are \"x+=+11\" or \"x+=+-6\" \r
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\n" ); document.write( "However, it's stated that the numbers are positive. So the only answer is \"x=11\"\r
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\n" ); document.write( "\n" ); document.write( "Now just plug that value into \"x-y=5\" and solve for 'y' to get \"11-y=5\" ---> \"y=11-5=6\"\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers are \"x=11\" and \"y=6\"\r
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\n" ); document.write( "\n" ); document.write( "Notice how 11-6=5. So their difference is 5\r
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\n" ); document.write( "\n" ); document.write( "Also, take note how \"11%5E2%2B6%5E2=121%2B36=157\".\r
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\n" ); document.write( "\n" ); document.write( "So this confirms our answer.
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