document.write( "Question 221389: In triangle ABC, angle A is twice as large as angle B. Angle B is 4 degrees larger than Angle C. Find the measure of each angle. \n" ); document.write( "
Algebra.Com's Answer #166059 by likaaka(51)\"\" \"About 
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You must set up a system of equations
\n" ); document.write( "The interior angles of a triangle always add up to 180°, so A + B + C = 180°
\n" ); document.write( "angle A is twice as large as angle B, so A = 2B
\n" ); document.write( "angle B is 4° larger than angle C ,so B = C + 4
\n" ); document.write( "First begin by solving for A in terms of C
\n" ); document.write( "if A = 2B and B = C + 4, then A = 2(C + 4) = 2C + 8
\n" ); document.write( "Now we have both angles A & B solved for in terms of C and we substitute them into the first equation
\n" ); document.write( "A + B + C = 180
\n" ); document.write( "(2C + 8) + (C + 4) + C = 180, the parenthesis are unnecessary here I just used them to show the substitution
\n" ); document.write( "Now combine like terms
\n" ); document.write( "4C + 12 = 180, subtract 12 from both sides
\n" ); document.write( "4C = 168, divide both sides by 4 to solve for C
\n" ); document.write( "C = 42, so angle C is 42°
\n" ); document.write( "Use C to solve for angles A & B
\n" ); document.write( "A = 2C + 8
\n" ); document.write( "A = 2(42) + 8
\n" ); document.write( "A = 84 + 8
\n" ); document.write( "A = 92, so angle A is 92°
\n" ); document.write( "B = C + 4
\n" ); document.write( "B = 42 + 4
\n" ); document.write( "B = 46, so angle B is 46° \n" ); document.write( "
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