document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220427>Question 220427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166048 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze?<BR>\n" );
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document.write( "The original 1 gallon of a/f will be 60% of the solution, s.<BR>\n" );
document.write( "1 gallon = 60% = 0.6s <BR>\n" );
document.write( "s = 1/0.6 = 5/3 gallons<BR>\n" );
document.write( "Add 2/3 gallons. </SPAN>\n" );
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