document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221308>Question 221308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation of the line that goes through the point (0,3/2) and is perpendicular to the line 5y=3x-4.   the equation has to be in standard form.  i dont know how to get rid of the fraction in the points. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166040 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write the equation of the line that goes through the point (0,3/2) and is perpendicular to the line 5y=3x-4. the equation has to be in standard form<BR>\n" );
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document.write( "Find the slope, m1, of 5y=3x-4<BR>\n" );
document.write( "5y=3x-4<BR>\n" );
document.write( "y = (3/5)x - 4/5<BR>\n" );
document.write( "m1 = 3/5<BR>\n" );
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document.write( "Lines perpendicular will have a slope that's the negative inverse, -5/3<BR>\n" );
document.write( "m2 = -5/3<BR>\n" );
document.write( "y = mx + b  thru (0,3/2)<BR>\n" );
document.write( "3/2 = (-5/3)*0 + b<BR>\n" );
document.write( "b = 3/2<BR>\n" );
document.write( "y = (-5/3)x + 3/2<BR>\n" );
document.write( "6y = -10x + 9<BR>\n" );
document.write( "10x + 6y = 9 </SPAN>\n" );
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