document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221269>Question 221269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 200 milimeters of a 49% acid solution but only has 37% and 57% acid solutions available.  Find how many milimeters of each that should ne mixed to get the desired solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #166005 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=166005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .57x+.37(200-x)=.49*200<BR>\n" );
document.write( ".57x+74-.37x=98<BR>\n" );
document.write( ".20x=98-74<BR>\n" );
document.write( ".20x=24<BR>\n" );
document.write( "x=24/.20<BR>\n" );
document.write( "x=120 ml. of th 57% mixture is used.<BR>\n" );
document.write( "200-120=80 ml of the 37% mixture is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".57*120+.37*80=.49*200<BR>\n" );
document.write( "68.4+29.6=98<BR>\n" );
document.write( "98=98 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );