document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221280>Question 221280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> negative 3 times the absolute value of 2 times a number minus 5 equals 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165997 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If this is what you meant  -3|2x-5|=15, then divide both sides by -3, and you get |2x-5|= -5.   There is NO SOLUTION since an absolute value cannot equal a negative number.\r<BR>\n" );
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document.write( "If you meant -3|2x|-5 = 15, then you begin by adding +5 to each side.<BR>\n" );
document.write( "-3|2x| = 20.  Next, divide by -3, and you get the same result:  absolute value cannot equal a negative number.  \r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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