document.write( "Question 221223: how many tons of hay at $125 per ton and $75 per ton must be purchased to have 100 tons of hay worth $9000? \n" ); document.write( "

Algebra.Com's Answer #165989 by sofiyac(983) $\"\"$ $\"About$

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$\"125x%2B75y=9000\"$
\n" ); document.write( " $\"x%2By=100\"$ so we have to solve this system of equations
\n" ); document.write( " $\"x=100-y\"$
\n" ); document.write( " $\"125%28100-y%29%2B75y=9000\"$
\n" ); document.write( " $\"12500-125y%2B75y=9000\"$
\n" ); document.write( " $\"12500-50y=9000\"$
\n" ); document.write( " $\"-50y=9000-12500\"$
\n" ); document.write( " $\"-50y=-3500\"$ divide both sides by -50
\n" ); document.write( " $\"y=70\"$
\n" ); document.write( " $\"x=100-70=30\"$
\n" ); document.write( "so we need 30 tons at $125/ton and 70 tons at $75/ton\r
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