document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221221>Question 221221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am performing mass balance equations and came across an equation I can not figure out because of the units.\r<BR>\n" );
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document.write( "(30 grams/sec)(QR)+(10 grams/cubic meter)(QR) = 40 grams/sec\r<BR>\n" );
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document.write( "QR is some value for a hypothetical water reservoir flow rate. Would I be able to subtract 30 and then solve by dividing 10?  I don't think I can because the units are not the same.\r<BR>\n" );
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document.write( "Please help.  Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165980 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You  are  right,,,10 g/sec  is  a  velocity<BR>\n" );
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document.write( "and  30 g/ cu mtr  is  a  density<BR>\n" );
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document.write( "if  we  did,,,,( 10 g/sec)/ (30 g /cu mtr) = (1/3) cu mtr / sec,,,,this  is  a  volume  exchange  rate.<BR>\n" );
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