document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221220>Question 221220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> S=(a-rl)/(1-r) solve for l     we get l=(a-S-Sr)/r  Bagatrix solver tells us the Sr should be positive, what step did we miss or mess up on. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165979 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S = (a-rl) / (1-r)<BR>\n" );
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document.write( "S*(1-r) = (a-rl)<BR>\n" );
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document.write( "S-Sr = a-rl<BR>\n" );
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document.write( "S-Sr -a = -rl<BR>\n" );
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document.write( "(S-Sr-a) / -r = l<BR>\n" );
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document.write( "(-S+Sr +a)/r = l<BR>\n" );
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document.write( "(a-S+Sr)/r = l </SPAN>\n" );
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