document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221122>Question 221122</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the complement of an angle is 5 degrees less than one-sixth of its supplement, find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165942 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the complement of an angle is 5 degrees less than one-sixth of its supplement, find the measure of the angle.\r<BR>\n" );
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document.write( "Step 1.  Supplementary angles means two angles add up to 180 degrees.\r<BR>\n" );
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document.write( "Step 2.  Complementary angles means two angles add up to 90 degrees.\r<BR>\n" );
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document.write( "Step 3.  Let a be the angle.\r<BR>\n" );
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document.write( "Step 4.  Let 180-a be the supplement of the angle a.\r<BR>\n" );
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document.write( "Step 5.  Let 90-a be the complement of the angle a.\r<BR>\n" );
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document.write( "Step 6.  Then  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-a=+%28180-a%29%2F6-5 ALIGN=MIDDLE  ALT=\"90-a=+%28180-a%29%2F6-5\"   DISABLED_style= \"max-width:90%; height:auto;\" >  since the complement of an angle is 5 degrees less than one-sixth of its supplement, find the measure of the angle.\r<BR>\n" );
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document.write( "Step 7.  Simplifying Step 6 yields the following steps:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-a=+%28180-a%29%2F6-5 ALIGN=MIDDLE  ALT=\"90-a=+%28180-a%29%2F6-5\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "Multiply by 6 to both sides of the equation to get rid of denominator\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2A%2890-a%29=+6%2A%28180-a%29%2F6-6%2A5 ALIGN=MIDDLE  ALT=\"6%2A%2890-a%29=+6%2A%28180-a%29%2F6-6%2A5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=540-6a=180-a-30 ALIGN=MIDDLE  ALT=\"540-6a=180-a-30\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Add 6a-150 to both sides of the equation to get variable a in left side and numbers on right side.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=540-6a%2B6a-150=150-a%2B6a-150 ALIGN=MIDDLE  ALT=\"540-6a%2B6a-150=150-a%2B6a-150\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=390=5a ALIGN=MIDDLE  ALT=\"390=5a\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide 5 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5a%2F5=390%2F5 ALIGN=MIDDLE  ALT=\"5a%2F5=390%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=78 ALIGN=MIDDLE  ALT=\"a=78\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-78=102 ALIGN=MIDDLE  ALT=\"180-78=102\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-78=12 ALIGN=MIDDLE  ALT=\"90-78=12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Check if equation in Step 6 is true...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-a=+%28180-a%29%2F6-5 ALIGN=MIDDLE  ALT=\"90-a=+%28180-a%29%2F6-5\"   DISABLED_style= \"max-width:90%; height:auto;\" >  or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12=102%2F6-5 ALIGN=MIDDLE  ALT=\"12=102%2F6-5\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is a true statement.\r<BR>\n" );
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document.write( "Step 7.  ANSWER:  Angle is 78 degrees, its supplementary angle is 102 degrees, and its complementary angle is 12 degrees\r<BR>\n" );
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document.write( "I hope the above steps and explanation were helpful. \r<BR>\n" );
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document.write( "For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. \r<BR>\n" );
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document.write( "Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.\r<BR>\n" );
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document.write( "Respectfully, <BR>\n" );
document.write( "Dr J\r<BR>\n" );
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document.write( " </SPAN>\n" );
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