document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221175>Question 221175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of angle b, the supplement of angle a, is four times the measure of angle c, the complement of angle a<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165932 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of angle b, the supplement of angle a, is four times the measure of angle c, the complement of angle a\r<BR>\n" );
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document.write( "Step 1.  Supplementary angles means two angles add up to 180 degrees.\r<BR>\n" );
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document.write( "Step 2.  Complementary angles means two angles add up to 90 degrees.\r<BR>\n" );
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document.write( "Step 3.  Let a be the angle.\r<BR>\n" );
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document.write( "Step 4.  Let b=180-a be the supplement of the angle a.\r<BR>\n" );
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document.write( "Step 5.  Let c=90-a be the complement of the angle a.\r<BR>\n" );
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document.write( "Step 6.  Then  180-a= 4(90-a) the measure of angle b, the supplement of angle a, is four times the measure of angle c, the complement of angle a.\r<BR>\n" );
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document.write( "Step 7.  Simplifying Step 6 yields the following steps:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-a=+360-4a ALIGN=MIDDLE  ALT=\"180-a=+360-4a\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Add 4a-180 to both sides of the equation to get variable a in left side and numbers on right side.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-a%2B4a-180=360-4a%2B4a-180 ALIGN=MIDDLE  ALT=\"180-a%2B4a-180=360-4a%2B4a-180\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3a=180 ALIGN=MIDDLE  ALT=\"3a=180\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide 3 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3a%2F3=180%2F3 ALIGN=MIDDLE  ALT=\"3a%2F3=180%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=60 ALIGN=MIDDLE  ALT=\"a=60\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-a=120 ALIGN=MIDDLE  ALT=\"180-a=120\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-a=30 ALIGN=MIDDLE  ALT=\"90-a=30\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Check if equation in Step 6 is true...180-a= 4(90-a) or 120=4*30 which is a true statement.\r<BR>\n" );
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document.write( "Step 7.  ANSWER:  Angle is 60 degrees, its supplementary angle is 120 degrees, and its complementary angle is 30 degrees\r<BR>\n" );
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document.write( "I hope the above steps and explanation were helpful. \r<BR>\n" );
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document.write( "For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. \r<BR>\n" );
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document.write( "Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.\r<BR>\n" );
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document.write( "Respectfully, <BR>\n" );
document.write( "Dr J\r<BR>\n" );
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