document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221039>Question 221039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer can plow a field in 4 days by using a tractor. A hired hand can plow the same field in 6 days by using a smaller tractor. How many days will be required for the plowing if they work together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165892 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if X is their combined time, then the FRACTION that the farmer plows is X/4<BR>\n" );
document.write( "___ and the FRACTION that the hired hand plows is X/6<BR>\n" );
document.write( "___ the FRACTIONS add to 1 (the WHOLE field)\r<BR>\n" );
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document.write( "X/4 + X/6 = 1\r<BR>\n" );
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document.write( "multiplying by 12 (LCD) ___ 3X + 2X = 12 ___ 5X = 12 ___ X = 12/5 = 2.4 days </SPAN>\n" );
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