document.write( "Question 221109: This has been troubling me for some time now: How many gallons of an 8% acid solution and a 22% acid solution need to be mixed to make 14 gallons of a 13% acid solution? \n" ); document.write( "
Algebra.Com's Answer #165882 by Alan3354(69443)\"\" \"About 
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This has been troubling me for some time now: How many gallons of an 8% acid solution and a 22% acid solution need to be mixed to make 14 gallons of a 13% acid solution?
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\n" ); document.write( "14 gal of 13% = 1.82 gal of acid
\n" ); document.write( "E + T = 14 (8% + 22%)
\n" ); document.write( "E*0.08 + T*0.22 = 1.82 (acid in solution)
\n" ); document.write( "8E + 22T = 182
\n" ); document.write( "E + T = 14 -->T = 14-E
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\n" ); document.write( "8E + 22(14-E) = 182
\n" ); document.write( "8E + 308 - 22E = 182
\n" ); document.write( "-14E = -126
\n" ); document.write( "E = 9 gallons
\n" ); document.write( "T = 5 gallons
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\n" ); document.write( "If they're mixed in equal amounts, the % will be the average, = 15%
\n" ); document.write( "Using more 8% will make the result less than 15%, as it does.
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