document.write( "Question 220956: The speed of a boat in still water is 10mph. It travels 15 miles upstream and 15 downstream in a total of 4 hours. what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #165868 by MathTherapy(10552)\"\" \"About 
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The speed of a boat in still water is 10mph. It travels 15 miles upstream and 15 downstream in a total of 4 hours. what is the speed of the current?\r
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\n" ); document.write( "\n" ); document.write( "Let speed of current = C\r
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\n" ); document.write( "\n" ); document.write( "Since speed in still water is 10 mph, then the speed to go upstream, against the current = 10 - C, and the speed downstream, with the current = 10 + C\r
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\n" ); document.write( "\n" ); document.write( "Now, since total trip took 4 hours to travel in both directions of 15 miles each, and since Time = \"D%2FS\", then we'll have: \"15%2F%2810+-+C%29+%2B+15%2F%2810+%2B+C%29+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "15(10 + C) + 15(10 - C) = 4 * (10 - C)(10 + C) ----- Multiplying by LCD (10 - C)(10 + C), in order to get rid of denominators\r
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\n" ); document.write( "\n" ); document.write( "\"150+%2B+15C+%2B+150+-+15C+=+4%28100+-+C%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"150+%2B+15C+%2B+150+-+15C+=+400+-+4C%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"4C%5E2+=+400+-+300\"\r
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\n" ); document.write( "\n" ); document.write( "\"4C%5E2+=+100\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%5E2+=+100%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%5E2+=+25\"\r
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\n" ); document.write( "\n" ); document.write( "\"C+=+sqrt%2825%29+=+5\" mph\r
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\n" ); document.write( "\n" ); document.write( "Therefore, speed of current = \"highlight_green%285%29\" mph \r
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\n" ); document.write( "\n" ); document.write( "Time upstream: \"15%2F%2810+-+5%29\" or \"15%2F5+=+3\" hours\r
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\n" ); document.write( "\n" ); document.write( "Time downstream: \"15%2F%2810+%2B+5%29\" or \"15%2F15+=+1\" hour\r
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\n" ); document.write( "\n" ); document.write( "Total time: (3 + 1) = 4 hours\r
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