document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=221071>Question 221071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been working on a problem using the elimination method. I think I have it right but would someone tell me if it is and if not what I have done wrong. The problem is 5r - 2s = 8<BR>\n" );
document.write( "               2r + 5s = 38<BR>\n" );
document.write( " I do not think there is a solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165859 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying 1st eqn by 5 ___ 25r - 10s = 40\r<BR>\n" );
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document.write( "multiplying 2nd eqn by 2 ___ 4r + 10s = 76\r<BR>\n" );
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document.write( "adding new eqns (this eliminates the s terms) ___ 29r = 116 ___ r = 4\r<BR>\n" );
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document.write( "substituting ___ 2(4) + 5s = 38 ___ 5s = 30 ___ s = 6 </SPAN>\n" );
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