document.write( "Question 221048: I need help on this word problem setting up the equation. A 2000L tank containing 550L of water is being filled with water at the rate of 75L per minute from a full 1600L tank. How long will it be before the two tanks have the same amount of water? X equals time. Not sure how to set up this equation and solve. \n" ); document.write( "
Algebra.Com's Answer #165846 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = number of minutes \n" ); document.write( "75 x = amount of water transferred\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1600-75x = amount of water in the larger tank after x minutes draining \n" ); document.write( "550 + 75x = amount of water in the tank being filled after x minutes of filling\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1600-75x = 550 + 75x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add +75x to each side. \n" ); document.write( "1600=550 + 75x+75x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 550 from each side: \n" ); document.write( "1050= 150x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 150 \n" ); document.write( "7=x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Final Answer = 7 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: After 7 minutes, 7*75 = 525 gallons of water transferred\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "550+525 = 1075 gallons in first tank \n" ); document.write( "1600-525 = 1075 gallons in second tank\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje \n" ); document.write( " |