document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220931>Question 220931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: The measure of the supplement of an angle is 3 times as great as the measure of the angle's complement. Find the measure of the angle. \r<BR>\n" );
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document.write( "Please help me solve this problem: The difference between the measures of the angle and its complement is 14. Find the measure of the angle and its complement. \r<BR>\n" );
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document.write( "Please help me solve this problem: Find the measure of an angle if it is 12 less than twice the measure of its complement. \r<BR>\n" );
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document.write( "Please help me solve this problem: If a point C is equidistant from points A and B, then point C is the midpoint of the segment that joins A and B.\r<BR>\n" );
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document.write( "Thank you for your time and help. Can you please explain them step by step? Sorry and thank you again. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165808 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All you have to know here is the definition of \"complement and supplement\"<BR>\n" );
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document.write( "The measure of the supplement of an angle is 3 times as great as the measure of the angle's complement. <BR>\n" );
document.write( "Find the measure of the angle.<BR>\n" );
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document.write( "let x = \"the angle\"<BR>\n" );
document.write( "supplement = 180-x<BR>\n" );
document.write( "complement = 90-x<BR>\n" );
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document.write( "The equation for what it says (the word \"is\" usually means =): <BR>\n" );
document.write( "180-x = 3(90-x)<BR>\n" );
document.write( "180 - x = 270 - 3x<BR>\n" );
document.write( "-x + 3x = 270 - 180<BR>\n" );
document.write( "2x = 90<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%2F2 ALIGN=MIDDLE  ALT=\"90%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 45 degrees<BR>\n" );
document.write( "You can check the solution in the original equation<BR>\n" );
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document.write( "The difference between the measures of the angle and its complement is 14.<BR>\n" );
document.write( " Find the measure of the angle and its complement.<BR>\n" );
document.write( "x - (90-x) = 14<BR>\n" );
document.write( "x - 90 + x = 14<BR>\n" );
document.write( "x + x = 14 + 90<BR>\n" );
document.write( "2x = 104<BR>\n" );
document.write( "x = 52 degrees<BR>\n" );
document.write( "Check solution in original equation<BR>\n" );
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document.write( "Find the measure of an angle if it is 12 less than twice the measure of its complement.<BR>\n" );
document.write( "x = 2(90-x) - 12<BR>\n" );
document.write( "x = 180 - 2x - 12<BR>\n" );
document.write( "x + 2x = 180 - 12<BR>\n" );
document.write( "3x = 168<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=168%2F3 ALIGN=MIDDLE  ALT=\"168%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 56 degrees<BR>\n" );
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document.write( "If a point C is equidistant from points A and B, then point C is the midpoint of the segment that joins A and B. OK, I agree with that!\r<BR>\n" );
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