document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220980>Question 220980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> George has 50 milliliters of a 10 percent acid solution. How many milliliters of 45 percent acid solution should he add to create a 35 percent acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165805 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .45x+.10*50=.35(50+x)<BR>\n" );
document.write( ".45x+5=17.5+.35x<BR>\n" );
document.write( ".45x-.35x=17.5-5<BR>\n" );
document.write( ".10x=12.5<BR>\n" );
document.write( "x=12.5/.10<BR>\n" );
document.write( "x=125 ml.of 45% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".45*125+.10*50=.35(50+125)<BR>\n" );
document.write( "56.25+5=.35*175<BR>\n" );
document.write( "61.25=61.25\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );