document.write( "Question 29844: Solve the inequality -3<5-2x/5<9
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Algebra.Com's Answer #16575 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
\"+-3%3C5-2x%2F5%3C9+\" this is an \"and\" type of equation.
\n" ); document.write( "The < < separate the problem into two separate problems
\n" ); document.write( "\"+-3%3C5-2x%2F5+\" and \"+5-2x%2F5%3C9+\"
\n" ); document.write( "They can be worked separately or simultaniously.
\n" ); document.write( "I will solve simultaniously.\r
\n" ); document.write( "\n" ); document.write( "\"+-3%3C5-2x%2F5%3C9+\" - 5 from 3 5 and 9
\n" ); document.write( "\"+-5=-5=-5+\"
\n" ); document.write( "\"+-8%3C-2x%3C4+\" divide all three parts by 2
\n" ); document.write( "\"+-8%3C-x%3C2+\" Problem here is we have a negative variable. with inequalities, when we multiply or divide by a - , the < or > flips.
\n" ); document.write( "\"+-8%3C-x%3C2+\" multiply by -1 to all parts and flip the < >
\n" ); document.write( "\"+8%3Cx%3C-2+\"
\n" ); document.write( "\"+8%3Ex%3E-2+\" Now to graph this .. we like the smallest # on the left. Flip the whole thing end for end.
\n" ); document.write( "\"+-2%3Cx%3C8+\" \r
\n" ); document.write( "\n" ); document.write( "The graph is a number line beginning at -2 and going to +8, but the circles at those points are open, since they are not greater than or equal to.\r
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