document.write( "Question 220907: When the Johnson triplets were three weeks old, their sleep habits were remarkably consistent. John slept for 3 hours and was awake for 30 minutes. Joan slept for 2 hours and was awake for 30 minutes. Jane slept for 2 hours 20 minutes and was awake for 40 minutes. On October 13 at 8:00 P.M., they all went to sleep at the same time. When did this event occur again? Give both the date and time.\r
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Algebra.Com's Answer #165737 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Each one has a different sleep-awake cycle:
\n" ); document.write( "John's is
\n" ); document.write( "\"3+%2B+1%2F2\" hrs
\n" ); document.write( "Joan's is
\n" ); document.write( "\"2+%2B+1%2F2\" hrs
\n" ); document.write( "Jane's is
\n" ); document.write( "\"2+%2B+1%2F3+%2B+2%2F3+=+3\" hrs
\n" ); document.write( "Call the lengths of these cycles \"a\",\"b\", and \"c\"
\n" ); document.write( "Now I can say
\n" ); document.write( "\"2a+=+7\"
\n" ); document.write( "\"2b+=+5\"
\n" ); document.write( "\"2c+=+6\"
\n" ); document.write( "Note that \"7%2A5%2A6+=+210\", and
\n" ); document.write( "\"2a+=+210%2F30\"
\n" ); document.write( "\"2b+=+210%2F42\"
\n" ); document.write( "\"2c+=+210%2F35\"
\n" ); document.write( "Finally, I can say
\n" ); document.write( "\"60a+=+210\"
\n" ); document.write( "\"84b+=+210\"
\n" ); document.write( "\"70c+=+210\"
\n" ); document.write( "60 sleep-awake cycles for John, 84 sleep-awake cycles for Joan
\n" ); document.write( "and 70 sleep-awake cycles for Jane all end together 210 hours
\n" ); document.write( "from Oct 13, 8 PM
\n" ); document.write( "\"210%2F24+=+8.75\" days
\n" ); document.write( "and
\n" ); document.write( "\".75%2A24+=+18\" hours
\n" ); document.write( "8 days would make it Oct 21, 8 PM
\n" ); document.write( "Adding 18 hours makes it
\n" ); document.write( "Oct 22, 2 PM they all go to sleep again at the same time
\n" ); document.write( "check answer
\n" ); document.write( "For John:
\n" ); document.write( "\"60%2A3.5+=+210\"
\n" ); document.write( "\"84%2A2.5+=+210\"
\n" ); document.write( "\"70%2A3+=+210\"
\n" ); document.write( "OK \r
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