document.write( "Question 220907: When the Johnson triplets were three weeks old, their sleep habits were remarkably consistent. John slept for 3 hours and was awake for 30 minutes. Joan slept for 2 hours and was awake for 30 minutes. Jane slept for 2 hours 20 minutes and was awake for 40 minutes. On October 13 at 8:00 P.M., they all went to sleep at the same time. When did this event occur again? Give both the date and time.\r
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Algebra.Com's Answer #165737 by josmiceli(19441) You can put this solution on YOUR website! Each one has a different sleep-awake cycle: \n" ); document.write( "John's is \n" ); document.write( " \n" ); document.write( "Joan's is \n" ); document.write( " \n" ); document.write( "Jane's is \n" ); document.write( " \n" ); document.write( "Call the lengths of these cycles \n" ); document.write( "Now I can say \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Note that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Finally, I can say \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "60 sleep-awake cycles for John, 84 sleep-awake cycles for Joan \n" ); document.write( "and 70 sleep-awake cycles for Jane all end together 210 hours \n" ); document.write( "from Oct 13, 8 PM \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "8 days would make it Oct 21, 8 PM \n" ); document.write( "Adding 18 hours makes it \n" ); document.write( "Oct 22, 2 PM they all go to sleep again at the same time \n" ); document.write( "check answer \n" ); document.write( "For John: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |