document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220881>Question 220881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are dealt one card from a 52 card deck. The the card is replaced in the deck, the deck is shuffled, and you draw again. Find the probability of getting a picture card the first time and a club the second time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165708 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are dealt one card from a 52 card deck. The the card is replaced in the deck, the deck is shuffled, and you draw again. Find the probability of getting a picture card the first time and a club the second time?<BR>\n" );
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document.write( "The events are independent.<BR>\n" );
document.write( "P(pic and club) = P(pic)*P(club) = 12/52*1/4 = 3/52 <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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