document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220770>Question 220770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok i have tried to keep up with my class. i go to an online high school and its hard for me to understand math i have searched my book and other resources but i can't figure out this problem. if you can provide any help or in-site that would be great\r<BR>\n" );
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document.write( "Question: A line perpendicular to x + 3y = 5 passes through (1,-1). What is the equation of the line in standard form. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165707 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A line perpendicular to x + 3y = 5 passes through (1,-1). What is the equation of the line in standard form.<BR>\n" );
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document.write( "Arrange the equation to slope intercept form to find the slope (m1)<BR>\n" );
document.write( "x + 3y = 5<BR>\n" );
document.write( "subtract x from both sides<BR>\n" );
document.write( "3y = -x + 5<BR>\n" );
document.write( "Divide both sides by 3<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The slope m1 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The relationship of perpendicular lines is given by m1*m2 = -1<BR>\n" );
document.write( "we know m1 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, find m2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F3 ALIGN=MIDDLE  ALT=\"-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >*m2 = -1<BR>\n" );
document.write( "Multiply both sides by -3<BR>\n" );
document.write( "m2 = -3(-1)<BR>\n" );
document.write( "m2 = +3<BR>\n" );
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document.write( "Use the point/slope formula to find the equation of the perpendicular line<BR>\n" );
document.write( "y - y1 = m(x - x1)<BR>\n" );
document.write( "Assign the values as follows: m=3; x1 = 1; y1 = -1<BR>\n" );
document.write( "y - (-1) = 3(x - 1)<BR>\n" );
document.write( "y + 1 = 3x - 3<BR>\n" );
document.write( "y = 3x - 3 - 1<BR>\n" );
document.write( "y = 3x - 4<BR>\n" );
document.write( "Put in the standard form <BR>\n" );
document.write( "3x - y = 4; is the equation of the perpendicular line<BR>\n" );
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document.write( "Did this make sense to you, any questions? </SPAN>\n" );
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