document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220884>Question 220884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is two less than the length.If the perimeter of the rectangle is 28 meters,find the dimension of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165703 by </B><A HREF=/tutors/aboutme.mpl?userid=l-mayfield><B>l-mayfield(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=l-mayfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation for P=2L+2W We know that W is 2 less than L => W=L-2 we can now plug that into the equation to solve.  28=2L + 2(L-2)  => 28 = 2L + 2L -4 you can rearrange the equation to read 2L + 2L -4 = 28.  Add 4 to both sides and combine like terms  => 4L = 32  now divide both sides by 4 to get L=8 and W =6<BR>\n" );
document.write( "Test: 2(8)+2(6) = 16 + 12 =28 </SPAN>\n" );
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