document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220869>Question 220869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lenght of a rectangle is five more than the width.If the perimeter of the rectangle is 18 meters,find the dimensions of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165700 by </B><A HREF=/tutors/aboutme.mpl?userid=l-mayfield><B>l-mayfield(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=l-mayfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=18 To find P you have 2L + 2W you know that L is equal to 5+W. Substitute the 5+W in the equation.  18=2L+2W => 18=2(5+W)+2W  => 18=10+2W+2W  => subtract 10 from both sides  18-10=10-10+2W+2W  => 8=4W  => divide both sides by 4 to get 2=W.  You know that L=5+W so 5+2 = 7.  L=7 and W=2.  Test 2(7)+2(2)=14+4=18 </SPAN>\n" );
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