document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220752>Question 220752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this. How much whipping cream and 2%milk should be mixed to obtain 35gallons of milk with 4% butterfat? 2%milk has 2% butterfat Whipping cream has 9% butterfat  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165659 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  m =  amt  milk,,,,and  c =  amt  of  cream,,,,both  in  gallons<BR>\n" );
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document.write( ".02m   +.09c = .04 (35)<BR>\n" );
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document.write( " but  m+c =35,,,,,or  m=35-c,,,,subst<BR>\n" );
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document.write( ".02(35-c) + .09 c = .04(35)<BR>\n" );
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document.write( ".7 -.02c + .09c = 1.4<BR>\n" );
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document.write( ".07c = .7<BR>\n" );
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document.write( "c= 10   gal,,,,,,,,,m=35-10=25 gal<BR>\n" );
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document.write( "checking,,,,,.02(25) + .09(10) = .04(35)<BR>\n" );
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document.write( ".5 + .9 = 1.4,,,,,ok<BR>\n" );
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