document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220722>Question 220722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve linear equation of two variables.plot three points to draw graph.5x-2y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165658 by </B><A HREF=/tutors/aboutme.mpl?userid=babydoll77stl><B>babydoll77stl(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=babydoll77stl><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-2y=6\r<BR>\n" );
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document.write( "subtrace 5x from both sides <BR>\n" );
document.write( "-2y=-5x+6\r<BR>\n" );
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document.write( "divide -2 by both sides to get y by itself\r<BR>\n" );
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document.write( "y= -5/-2x+6/-2\r<BR>\n" );
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document.write( "y= 5/2x-3\r<BR>\n" );
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document.write( "-3 is your starting point on the y axis\r<BR>\n" );
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document.write( "5/2 is your rise over run\r<BR>\n" );
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document.write( "start at -3 on the y-axis, then rise 5 points and then go to the right 2 points since the number is now negative.  You can do this same step more than once so you have more than 2 points on the graph to draw your line.  \r<BR>\n" );
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document.write( "It's easier to have at least 3 points on the graph </SPAN>\n" );
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