document.write( "Question 220734: Solve for x:
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document.write( "2x+1 <3
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document.write( "x-5\r
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document.write( "I tried this:\r
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document.write( "x and x cancel eachother so its\r
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document.write( "x+1 <3
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document.write( "-5\r
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document.write( "then multiply the demonator and numerator by 5/1 so that leaves x<3??? \n" );
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Algebra.Com's Answer #165634 by tutor_paul(519)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Whoa there... you can't cancel the x's in this case...you can only cancel factors, not when x is added to something. \n" ); document.write( "In this case, first multipy each side of the inequality by (x-5): \n" ); document.write( " \n" ); document.write( "Now you can cancel the x-5 terms on the left because they are factors. This leaves you with: \n" ); document.write( " \n" ); document.write( "Now multipy out the term on the right: \n" ); document.write( " \n" ); document.write( "Next you want to get the x terms on one side of the inequality and other terms on the other side. \n" ); document.write( "Add -3x to both sides: \n" ); document.write( " \n" ); document.write( "Simplify: \n" ); document.write( " \n" ); document.write( "Add -1 to each side: \n" ); document.write( " \n" ); document.write( "Simplify: \n" ); document.write( " \n" ); document.write( "Multiply each side by -1. Note, when you multiply each side by a negative number, you must swap the inequality: \n" ); document.write( " \n" ); document.write( "============== \n" ); document.write( "Good Luck, \n" ); document.write( "tutor_paul@yahoo.com \n" ); document.write( " \n" ); document.write( " |