document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220587>Question 220587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity of a 80% acid solution must be mixed with a 30% solution to produce 600 ml of a 40% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165566 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 80% solution needed<BR>\n" );
document.write( "Then 600-x=amount of 30% solution needed<BR>\n" );
document.write( "Now we know that the pure acid in the 80% solution (0.80x) plus the amount of pure acid in the 30% solution ((0.30)(600-x)) has to equal the amount of pure acid in the final mixture(0.40*600), so our equation to solve is:\r<BR>\n" );
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document.write( "0.80x+0.30(600-x)=0.40*600  get rid of parens<BR>\n" );
document.write( "0.80x+180-0.30x=240 subtract 180 from each side<BR>\n" );
document.write( "0.80x+180-180-0.30x=240-180  collect like terms<BR>\n" );
document.write( "0.50x=60  divide each side by 0.50<BR>\n" );
document.write( "x=120 ml---------------------amount of 80% solution needed<BR>\n" );
document.write( "600-x=600-120=480 ml---------------amount of 30% solution needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "120*0.80+480*0.30=0.40*600<BR>\n" );
document.write( "96+144=240<BR>\n" );
document.write( "240=240\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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