document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220559>Question 220559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please explain to me how to combine the terms of the expression into only one logarithm. \r<BR>\n" );
document.write( "\n" );
document.write( "log3(x)+log3(x+2)-log2(3x-4)^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165547 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Could you please explain to me how to combine the terms of the expression into only one logarithm. <BR>\n" );
document.write( "log3(x)+log3(x+2)-log2(3x-4)^2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Solve 3^y = 2<BR>\n" );
document.write( "y = ln2/ln3 = 0.6309<BR>\n" );
document.write( "-------------------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "log3[x(x+2)] - 0.6309log3[(3x-4)^2]<BR>\n" );
document.write( "log3[x(x+2)] - log3(3x-4)^(2(0.6309))<BR>\n" );
document.write( "----<BR>\n" );
document.write( "log3[x(x+2)/(3x-4)^1.2619]<BR>\n" );
document.write( "==============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );