document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220461>Question 220461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3x<-9 or 2x>6x-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165537 by </B><A HREF=/tutors/aboutme.mpl?userid=bakerrrr><B>bakerrrr(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bakerrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3x<-9 or 2x>6x-4. This is a disjunction.\r<BR>\n" );
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document.write( "The first step is to solve the one on the left...<BR>\n" );
document.write( "so divide by three, to find x.\r<BR>\n" );
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document.write( "-3x<-9 divide by three. X>3. The < sign switches to > because you are dividing by a negative number.\r<BR>\n" );
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document.write( "The second one... 2x>6x-4. Subtract 6x from both sides. <BR>\n" );
document.write( "2x-6x=-4. So now there is -4x>-4. Divide and the answer is x<1.\r<BR>\n" );
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document.write( "Then make a number line... and plot the two points. Using open circles. One on 3, with an arrow pointing towards all of the greater numbers, and an open circle on 1 with all of the numbers less than it. </SPAN>\n" );
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