document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220545>Question 220545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 105. The second number is 10 larger than the first and the third is one-half the second. Find the three numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165530 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 105. The second number is 10 larger than the first and the third is one-half the second. Find the three numbers.<BR>\n" );
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document.write( "a + b + c = 105<BR>\n" );
document.write( "b = a+10<BR>\n" );
document.write( "c = (1/2)b<BR>\n" );
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document.write( "Rearrange:<BR>\n" );
document.write( "a + b + c = 105<BR>\n" );
document.write( "a - b + 0 = -10<BR>\n" );
document.write( "0 + b -2c =  0<BR>\n" );
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document.write( "Use any method you know to find:<BR>\n" );
document.write( "a = 36<BR>\n" );
document.write( "b = 46<BR>\n" );
document.write( "c = 23<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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