document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220415>Question 220415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "mr c is twice as old as his son,in 42 years the ratio of their ages will be4:3 what is the sons age<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165479 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ages are x for the son & 2x for the mr. now<BR>\n" );
document.write( "in 42 years they will be x+42 for the son & 2x+42 for the mr.<BR>\n" );
document.write( "4/3=(2x+42)/(x+42)<BR>\n" );
document.write( "3(2x+42)=4(x+42)<BR>\n" );
document.write( "6x+126=4x+168<BR>\n" );
document.write( "6x-4x=168-126<BR>\n" );
document.write( "2x=42<BR>\n" );
document.write( "x=42/2<BR>\n" );
document.write( "x=21 is the age of the son now.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "4/3=(2*21+42)/21+42)<BR>\n" );
document.write( "4/3=(42+42)/63<BR>\n" );
document.write( "4/3=84/63<BR>\n" );
document.write( "3*84=4*63<BR>\n" );
document.write( "252=252<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );