document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29609>Question 29609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> is this how u condense this problem log3a+ log 3b +1= log3ab  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16544 by </B><A HREF=/tutors/aboutme.mpl?userid=Cintchr><B>Cintchr(481)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cintchr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The [#] is the base of the log<BR>\n" );
document.write( "You are close.  is it b or (b+1)? <BR>\n" );
document.write( "log[3]a+ log[3]b + 1 = log[3]ab<BR>\n" );
document.write( "if b+1 .....<BR>\n" );
document.write( "log[3]a + log[3](b+1) = log[3]a(b+1)<BR>\n" );
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