document.write( "Question 220275: The monthly payment on a 2-year loan is $500. The interest rate is 6.65% compunded monthly. What is the amount of the loan? \n" ); document.write( "
Algebra.Com's Answer #165421 by Theo(13342)![]() ![]() You can put this solution on YOUR website! Formula for present value of a series of payments is: \n" ); document.write( "PRESENT VALUE OF A PAYMENT \n" ); document.write( " \n" ); document.write( "PV = present value \n" ); document.write( "PMT = payment per time period \n" ); document.write( "i = interest rate per time period \n" ); document.write( "n = number of time periods \n" ); document.write( "----- \n" ); document.write( "6.55% per year compounded monthly is: \n" ); document.write( "6.55/12 = .554166667% per month which equals a rate of: \n" ); document.write( ".00554166667 per month. \n" ); document.write( "Number of month is 2 years * 12 months = 24 months \n" ); document.write( "payment is $500 per month. \n" ); document.write( "----- \n" ); document.write( "PV = what we want to find. \n" ); document.write( "PMT = $500 per month \n" ); document.write( "i = .00554166667 per month \n" ); document.write( "n = 24 months \n" ); document.write( "Formula becomes: \n" ); document.write( " \n" ); document.write( "which equals: $11,224.28901 \n" ); document.write( "----- \n" ); document.write( "The loan was $11,224.28901 \n" ); document.write( "The lender received $12,778.06 by the end of the loan (Future Value of a Series of Payments). \n" ); document.write( "Principal was $11,224.29 \n" ); document.write( "Interest was $1,553.77 \n" ); document.write( " |