document.write( "Question 29809: (x^2-x)^2 - 14(x^2-x) + 24 = 0 \n" ); document.write( "

Algebra.Com's Answer #16541 by Cintchr(481) $\"\"$ $\"About$

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$\"+%28x%5E2-x%29%5E2+-+14%28x%5E2-x%29+%2B+24+=+0+\"$
\n" ); document.write( "first, distribute the power on the first quantity by multiplying the exponents.
\n" ); document.write( " $\"+%28x%5E4-x%5E2%29+-+14%28x%5E2-x%29+%2B+24+=+0+\"$ the distribute the 14 to the quantity dont forget to watch your signs
\n" ); document.write( " $\"+%28x%5E4-x%5E2%29+-+14x%5E2%2B14x+%2B+24+=+0+\"$ combine like terms
\n" ); document.write( " $\"+%28x%5E4%29+%2B+highlight+%28-1x%5E2+-+14x%5E2%29+%2B+14x+%2B+24+=+0+\"$
\n" ); document.write( " $\"+x%5E4+-+15x%5E2+%2B+14x+%2B+24+=+0+\"$ with 4 terms, you have to factor two of them at a time to find a common factor\r
\n" ); document.write( "\n" ); document.write( " $\"+highlight+%28x%5E4+-+15x%5E2%29+%2B+highlight+%2814x+%2B+24%29+=+0+\"$
\n" ); document.write( " $\"+x%5E2%28x%5E2+-+15%29+%2B+2%287x+%2B+12%29+=+0+\"$ I can not get it to factor from here. Check your signs in the original problem. Are they correct?
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