document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220180>Question 220180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane has 35 coins consisting of nickels and quaters. If the total value of the coins is $4.95, how many nickels and how many quarters does she have? You must show the equations and the work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165405 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK, we'll deal in pennies.<BR>\n" );
document.write( "Let x=number of nickels; value of the nickels =5x<BR>\n" );
document.write( "Then 35-x=number of quarters; value of the quarters=25(35-x)<BR>\n" );
document.write( "And we are told that the above values add up to 495, so our equation to solve is:<BR>\n" );
document.write( "5x+25(35-x)=495 divide each term by 5----just to reduce the size of the numbers<BR>\n" );
document.write( "x+5(35-x)=99  get rid of parens<BR>\n" );
document.write( "x+175-5x=99  subtract 175 from each side<BR>\n" );
document.write( "x+175-175-5x=99-175  collect like terms<BR>\n" );
document.write( "-4x=-76  divide each side by -4<BR>\n" );
document.write( "x=19-----------number of nickels<BR>\n" );
document.write( "35-x=35-19=16 number of quarters<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "19*5+16*25=495<BR>\n" );
document.write( "95+400=495<BR>\n" );
document.write( "495=495\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );