document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220209>Question 220209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John invested $20,000 in two different accounts, one paying 7% and the other 9%.  If total interest earned for the year was $1,550, how much was invested in each account. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165367 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the amount invested at 9% then (20,000-x) would be the amount invested at 7%.  The interest on these two amounts can be expressed as:<BR>\n" );
document.write( "0.09x+0.07(20000-x) = $1,550 Simplify this and solve for x.<BR>\n" );
document.write( "0.09x+1400-0.07x = 1550<BR>\n" );
document.write( "0.02x+1400 = 1550<BR>\n" );
document.write( "0.02x = 150 then...<BR>\n" );
document.write( "x = 7,500 and 20,000-x = $12,500<BR>\n" );
document.write( "$7,500 was invested at 9% and $12,500 was invested at 7%<BR>\n" );
document.write( " </SPAN>\n" );
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