document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=220147>Question 220147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the substitution method to solve the following system of linear equations.\r<BR>\n" );
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document.write( "-3x  - y = 3<BR>\n" );
document.write( "-3x - 5y = -21\r<BR>\n" );
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document.write( "what is the solution?\r<BR>\n" );
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document.write( "(__,__) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165348 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -(-3x  - y = 3 ) multiply this equation by -1 & add.<BR>\n" );
document.write( "-3x - 5y = -21<BR>\n" );
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document.write( "-4y=-24<BR>\n" );
document.write( "-4y=-24<BR>\n" );
document.write( "y=-24/-4<BR>\n" );
document.write( "y=6 ans.<BR>\n" );
document.write( "-3x-6=3<BR>\n" );
document.write( "-3x=3=6<BR>\n" );
document.write( "-3x=9<BR>\n" );
document.write( "x=9/-3<BR>\n" );
document.write( "x=-3 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "-3*-3-5*6=-21<BR>\n" );
document.write( "9-30=-21<BR>\n" );
document.write( "-21=-21\r<BR>\n" );
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document.write( "what is the solution?\r<BR>\n" );
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document.write( "(-3,6) </SPAN>\n" );
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