document.write( "Question 220103: What are the steps to solving this problem? (2/(x-1))-(5/x)=(10/(x^2-x)) \n" ); document.write( "
Algebra.Com's Answer #165316 by ptaylor(2198)\"\" \"About 
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What are the steps to solving this problem? (2/(x-1))-(5/x)=(10/(x^2-x))\r
\n" ); document.write( "\n" ); document.write( "Step 1: Observe that on the right side, the denominator, (x^2-x) can be factored to x(x-1), so let's do that and re-write the equation. Now we have:
\n" ); document.write( "2/(x-1)-(5/x)=10/x(x-1)\r
\n" ); document.write( "\n" ); document.write( "Step 2: Observe that if we multiply each term in the equation by x(x-1), we completely rid ourselves of the fractions. Now let's do that:
\n" ); document.write( "(2x(x-1))/(x-1) -(5x(x-1))/x =10x(x-1)/x(x-1) simplify by cancelling and we get:
\n" ); document.write( "2x-5(x-1)=10 \r
\n" ); document.write( "\n" ); document.write( "Step3: we simplify the above equation by getting rid of parens and collecting like terms and we get
\n" ); document.write( "2x-5x+5=10 subtract 5 from each side
\n" ); document.write( "2x-5x+5-5=10-5 collect like terms
\n" ); document.write( "-3x=5 divide each side by -3
\n" ); document.write( "x=-(5/3)----------answer\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "Substitute x=-(5/3) in the original equation:
\n" ); document.write( "(2/((-5/3)-1))-(5/(-5/3)=(10/((-5/3)^2-(-5/3))
\n" ); document.write( "2/(-8/3)-(-3)=10/(25/9+15/9)
\n" ); document.write( "(-6/8)+(24/8)=9/4
\n" ); document.write( "18/8=9/4
\n" ); document.write( "9/4=9/4\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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