document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219856>Question 219856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem:  \r<BR>\n" );
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document.write( "How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? use the six step method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165274 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of<BR>\n" );
document.write( " 25% antifreeze to get a mixture that is 60% antifreeze?<BR>\n" );
document.write( " use the six step method<BR>\n" );
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document.write( "I'm not sure what the six step method, but this is how I would do it<BR>\n" );
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document.write( "Let x = amt of  70% solution will be required<BR>\n" );
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document.write( "A simple mixture equation<BR>\n" );
document.write( ".70x + .25(70) = .60(x + 70)<BR>\n" );
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document.write( ".70x + 17.5 = .60x + 42<BR>\n" );
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document.write( ".70x - .60x = 42 - 17.5<BR>\n" );
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document.write( ".10x = 24.5<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=24.5%2F.10 ALIGN=MIDDLE  ALT=\"24.5%2F.10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 245 gal of 70% solution<BR>\n" );
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document.write( "Check solution in the original equation<BR>\n" );
document.write( ".70(245) + .25(70) = .60(245 + 70)<BR>\n" );
document.write( "171.5 + 17.5 = .60(315)<BR>\n" );
document.write( "189 = 189 </SPAN>\n" );
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