document.write( "Question 29803: A garden is in the shape of a trapezoid. If the height of the trapezoid is 16 m, one base is 20 m, and the area is 224m^2, find the lenght of the other base. \n" ); document.write( "
Algebra.Com's Answer #16527 by venugopalramana(3286)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "SEE THE TRAPEZOID ....ABCD below
\n" ); document.write( "AREA OF TRAPEZOID IS GIVEN BY
\n" ); document.write( "AREA=(1/2)*ALTITUDE*(SUM OF PARALLEL SIDES)=(1/2)*DP*(AB+CD)
\n" ); document.write( "WHERE ALTITUDE IS THE PERPENDICULAR DISTANCE BETWEEN PARALLEL SIDES =DP
\n" ); document.write( "PARALLEL SIDES ARE AB AND CD.
\n" ); document.write( "WE HAVE AB=40
\n" ); document.write( "BC=AD=20
\n" ); document.write( "ANGLE DAP=63
\n" ); document.write( "DAP IS A RIGHT ANGLED TRIANGLE...DP/DA=SIN(63)
\n" ); document.write( "DP=DA*SIN(63)=20*0.89=17.8
\n" ); document.write( "SO ALTITUDE=17.8
\n" ); document.write( "AP/DA=COS(63)
\n" ); document.write( "AP=DA*COS(63)=20*0.4545=9.1
\n" ); document.write( "SO CD =AB-2*AP SINCE TRAPEZOID IS ISOCELLES..
\n" ); document.write( "CD=40-2*9.1=21.8
\n" ); document.write( "AREA=(1/2)17.8(40+21.8)=550 SQUARE UNITS.
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