document.write( "Question 219959: How do you solve the equation:
\n" ); document.write( "square root of(5-x)=x-3
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Algebra.Com's Answer #165260 by stanbon(75887)\"\" \"About 
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solve the equation:
\n" ); document.write( "square root of(5-x)=x-3
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\n" ); document.write( "sqrt(5-x) = x-3
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "5-x = x^2-6x+9
\n" ); document.write( "x^2-5x+4 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(x-4)(x-1) = 0
\n" ); document.write( "x = 4 or x = 1
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\n" ); document.write( "Check in the original equation:
\n" ); document.write( "If x=4 you get: sqrt(1) = 4-3 which is correct.
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\n" ); document.write( "If x=1 you get sqrt(4) = 1-3 which is not correct.
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\n" ); document.write( "Solution: x = 4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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