document.write( "Question 219880: May rides her bike the same distance that Leah walks. May rides her bike 10km/h faster than Leah walks. If it takes May 1 h and Leah 3 h to travel that distance, how fast does each travel ? \n" ); document.write( "
Algebra.Com's Answer #165240 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! May rides her bike the same distance that Leah walks. \n" ); document.write( " May rides her bike 10km/h faster than Leah walks. \n" ); document.write( " If it takes May 1 h and Leah 3 h to travel that distance, how fast does each travel ? \n" ); document.write( "; \n" ); document.write( "Let s = L's walking speed \n" ); document.write( "then \n" ); document.write( "(s+10) = M's biking speed \n" ); document.write( ": \n" ); document.write( "The both travel the same distance, write a distance equation D = time * speed \n" ); document.write( ": \n" ); document.write( "L's dist = M's dist \n" ); document.write( "3s = 1(s+10) \n" ); document.write( "3s = s + 10 \n" ); document.write( "3s - s = 10 \n" ); document.write( "2s = 10 \n" ); document.write( "s = 5 mph is L's walking speed \n" ); document.write( "and \n" ); document.write( "5 + 10 = 15 mph is M's biking speed \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Confirm solution by finding the distance of each \n" ); document.write( "3(5) = 1(15) \n" ); document.write( " |