document.write( "Question 219776: A radiator contains 15 gal of a 20% antifreeze solution. How many gallons must be drained from the radiator and replaced by pure antifreeze so that the radiator will contain 15 gal of a 40% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #165206 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! (15*.20)-(x*.20)+x=15*.40 \n" ); document.write( "3-.2x+x=6 \n" ); document.write( ".8x=6-3 \n" ); document.write( ".8x=3 \n" ); document.write( "x=3/.8 \n" ); document.write( "x=3.75 gal. of pure antifreeze is used. \n" ); document.write( "Proof: \n" ); document.write( "3-3.75*.20+3.75=6 \n" ); document.write( "3-.75+3.75=6 \n" ); document.write( "6=6 \n" ); document.write( " |