document.write( "Question 219673: a rectangular soccer field has perimeter 360 yd. its length is 20 yd more than its width. what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #165159 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! P=2w+2l \n" ); document.write( "360=2x+2(x+20) \n" ); document.write( "360=2x+2x+40 \n" ); document.write( "320=4x \n" ); document.write( "x=80yds \n" ); document.write( "x+20=100yds \n" ); document.write( " |